A construction company is setting up signs on a 6 3/4 mile stretch of road. If the company places a sign every 3/4 of a mile, how many signs will it need? Note: the company will place a Sign at the beginning of the stretch,
then every 3/4 of a mile.

10

Step-by-step explanation:

6 3/4 ÷ 3/4 = 9, and plus the sign at the start of the road it would be 10

hope this helps :)

a: 1/6, j: 1/4

step-by-step explanation: you are welcome

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)