Ashipment of beach balls with a mean diameter of 28 cm and a standard deviation of 1.3 cm is normally distributed. by how many standard deviations does a beach ball with a diameter of 26.7 cm differ from the mean?
a-1
b-1.3
c-2
d-3

A. -1

Step-by-step explanation:

We have been given that a shipment of beach balls with a mean diameter of 28 cm and a standard deviation of 1.3 cm is normally distributed.  

Since z-score represents that a raw score is how many standard deviation above or below mean.

To solve our given problem we will use z-score formula.

, where,

,

,

,

.

Upon substituting our given values in z-score formula we will get,

Therefore, a beach ball with a diameter of 26.7 cm differs -1 standard deviation from the mean and option A is the correct choice.

1/4 because there is 4 grades.

actually your concept is wrong

step-by-step explanation:

150% of x =300

150x=300×100

x=(300×100)÷150

x=200