If A boy leaps over a rock, What is the equal and opposite force for the force of the boy pushing on the ground as described by Newton's third
law?

normal force of the ground pushing the boy up

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step-by-step explanation:

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for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2