In ΔIJK, the measure of ∠K=90°, the measure of ∠J=62°, and KI = 2.7 feet. Find the length of IJ to the nearest tenth of a foot

thanks this will be helpful somehow lol

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

there is no question content here, but you for the free points! : d