Find the product: 9x(x3-4x2-3x)

9x^4-36x^3-27x^2

Step-by-step explanation:

assuming those are exponents

9x^4 - 36x^3 - 27x^2

Step-by-step explanation:

9x(x^3 - 4x^2 - 3x)

Multiply 9x to each of the terms in the parentheses:

9x^4 - 36x^3 - 27x^2

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes