A bag contains x yellow balls, 2x + 1 green balls and 3x + 2 black balls. There are 39 balls in the bag. Find the numbers of yellow, green and black balls in the bag

no. of yellow balls = x = 6

no. of green balls= 2x+1= 2×6+1= 13

no of black balls= 3x+2= 3×6+2= 20

Step-by-step explanation:

we can write it as

x+ 2x+1 + 3x+ 2 = 39

6x+3=39

6x=39-3

6x= 36

x= 36/6

x= 6

no. of yellow balls = x = 6

no. of green balls= 2x+1= 2×6+1= 13

no of black balls= 3x+2= 3×6+2= 20

4sqrt5

step-by-step explanation:

the base has dimensions of 8 x 4, so the diagonal is 64 + 16 square rooted or 4sqrt5.