HELP ME PLEASE! Complete the work to find the equation of a line that passes through point (–5, –3) and is parallel to line y – 3x = –7. Step 1: Write the equation of the given line in slope intercept form: y = 3x – 7. Step 2: Determine the slope of the parallel line: m = 3. Step 3: Substitute the slope and given point into y = mx + b to find the y-intercept of the new line. –3 = 3 (–5 ) + b 3 = –15 + b b = 12 Step 4: Write the equation of the line parallel to 3x – y = 7 that passes through point (–5, –3).

Y=3x+12 (its the first option)

Step-by-step explanation:

I did the assignment.

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

50- 250 is correct i did that one too

step-by-step explanation: