A company sells 14 types of crackers that they label varieties 1 through 14, based on spice level. What is the probability that the purchase results in a selection of a cracker with an odd number, or a number greater than 11?

The required probability is

Step-by-step explanation:

Probability: Rule of Addition

The probability that Event A or Event B occurs is equal to the probability that Event A occurs plus the probability that Event B occurs minus the probability that both Events A and B occur. It can be calculated as follows:

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

There are 14 types of crackers the company sells, numbered from 1 to 14. The sample space for purchasing one cracker is:

There are n=14 possible choices.

The favorable cases for a cracker with an odd number are:

A = {1,3,5,7,9,11,13}

There are 7 favorable cases.

The favorable cases for a cracker with a number greater than 11 are:

B = {12,13,14}

There are 3 favorable cases.

The cases which are common to both events are:

A ∩ B= {13}

There is 1 case.

The probability of each event is:

Therefore:

Adding the fractions:

The required probability is

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation: