A businessman is paid $12 per hour and $10 for each sale he makes. He wants to earn more than $250 in an 10-hour work period. Write an inequality that represents the number of sales, x, the businessman must make in an 10-hour period to earn more than $250.

What is the least number of sales he must make to reach his goal?

Multiply hotly rate by hours worked, he want to work 10’hours so 12 x 10 =120

Add that to number of sales x amount earned per sale: 10s

Now you have 120 + 10s

He wants to earn at least 250:

120 + 10s >= 250

Now solve for a

Subtract 120 from both sides:

10s >= 130

Divide both sides by 10:

S >= 13

Minimum sales need to be 13

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following