Write a quadratic equation in standard form with roots -2 and -5

To solve this problem. First lets work our way backwards and try to figure out the binomials that will result in these roots.

-2 root = X int = -2
Thus it would be (X +2) because if you solve for x the solution or X intercept is -2.
Same thing for -5.
(X+5).

Next place them together and multiply or foil to obtain the quadratic.

Y = (X+5)(X+2)
Y = X^2 + 7x + 10

Standard form = Ax^2 +/- Bx +/- C = 0.

The standard form is X^2 + 7x + 10.