A boy at an amusement park has 65 ride tickets. Each ride on the roller coaster costs 7 tickets. After riding the roller coaster as many times as he can, how many tickets will the boy have left?

The boy will have 2 tickets left.

Step-by-step explanation:

First you have to figure out how many times 7 goes into 65. As 65 is not a multiple of 7, you have to look for the closest number. In this case, 7*9=63. That is the closest number to 65 that is also a multiple of 7, so the boy can ride the roller coaster 9 times. Since the question is asking how many tickets the boy will have left, you simply subtract 65-63=2. So, the boy will have 2 tickets left.

Hope this helped :)

3 is greater then both of those numbers

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