In ΔRST, \text{m}\angle R = (11x+3)^{\circ}m∠R=(11x+3) ∘ , \text{m}\angle S = (x+15)^{\circ}m∠S=(x+15) ∘ , and \text{m}\angle T = (2x+8)^{\circ}m∠T=(2x+8) ∘ . Find \text{m}\angle R. M∠R.

<R = 124°

Step-by-step explanation:

Note that the sum of angles in a triangle is 180degrees. In a triangle RST

Given

∠R=(11x+3)°

∠S=(x+15)°

∠T=(2x+8)°

Required

∠R

First we need to get the value of x;

since <R+<S+<T = 180

11x+3+x+15+2x+8 = 180

11x+x+2x+3+15+8 = 180

14x+26 = 180

14x = 180-26

14x = 154

x = 154/14

x = 11°

get <R

Since <R = 11x+3

<R = 11(11)+3

<R = 121+3

<R = 124°

Hence the measure of <R is 124°

this may not be at all, but i use the same website you're using for school, and if i'm stuck doing one of these i try to look for it on the section.

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol