In a survey, of the voters support a particular referendum. If 40 voters are chosen at random, find the mean and variance for the number of voters who support the referendum.

This question is incomplete, the complete question is;

In a survey, 55% of the voters support a particular referendum. If 40 voters are chosen at random,

find the mean and variance for the number of voters who support the referendum.

a) The Mean is 22

b) Variance is 9.9

Step-by-step explanation:

Given that;

55% of the voters support a particular referendum p = 0.55

q = 1 - p = 1 - 0.55 = 0.45

sample size n = 40

a)

Mean = sample size n × p

Mean = 40 × 0.55

Mean = 22

Therefore the Mean is 22

b)

Variance = n × p × q

so we substitute

Variance = 40 × 0.55 × 0.45

Variance = 9.9

Therefore the Variance is 9.9

81 seats

step-by-step explanation:

if you multiply 0.65 times 125 then you get 81.5 seats. well since you can't have half of a seat you have to round down and get 81 seats in the no children zones. that leave 44 seats outside of the no children zone.

y=1/4x-4

step-by-step explanation: