What is the equation of a line, in point-slope form, that passes through (-8, 1) and has a slope of 5/6?

y-1=(x+8)

Step-by-step explanation:

1. y-y1=m(x-x1) (point slope form)

2. y1 is the y of your given point and x1 is the x of your given point

3. m is the slope

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm