A metallurgist wants to make 130 grams of an alloy that is to be 20% copper. She has samples that are 14% copper and 22% copper. How many grams of the sample that contains 14% should she use?

She should use 32.5 g of the sample that contains 14%

Step-by-step explanation:

Here, we want to know the number of grams of the sample that contains 14% copper that should be used

let the number of grams that contains 14% copper to be used be x

Then the number of grams of 22% will be 130-x

Thus, mathematically;

0.14(x) + 0.22(130-x) = 0.2(130)

0.14x + 28.6 - 0.22x = 26

0.22x - 0.14x = 28.6 - 26

0.08x = 2.6

x = 26/0.08

x = 32.5

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

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step-by-step explanation: