Find the slope and the y-intercept of the equation y-3(x - 1) = 0. OA.
slope = -3 and y-intercept = -3
OB. slope = 3 and y-intercept = 3
OC. slope = -3 and y-intercept = 3
OD. slope = 3 and y-intercept = -3

OD is the answer

Step-by-step explanation:

y - 3(x - 1) = 0

y - 3x + 3 = 0

y = 3x - 3

therefore, slope = 3 and y intercept = -3

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.