Mathematics, 10.11.2020 01:00 Raquelerol
An object is launched at 18.4 meters per second (m/s) from a 36.8-meter tall
platform. The equation for the object's height s at time t seconds after launch is
s(t) = –4.9t2 + 18.4t + 36.8, where s is in meters.
When does the object strike the ground?
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How long did it take to get to its maximum height?
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What was the height of the object at 3.32 seconds?
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Answers: 2
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An object is launched at 18.4 meters per second (m/s) from a 36.8-meter tall
platform. The equation...
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