Two cans have volumes of 64cm³ and 125cm³. If the larger can has a surface area of 50cm², what is the surface area of the smaller can?

Surface area of the smaller can = 32cm³

Step-by-step explanation:

Volume of the bigger can = 125cm³

Volume of the smaller can = 64cm³

Surface area of the smaller can = xcm³

Surface area of the larger can = 50cm³

V = s³

Volume of the bigger can = 125cm³

125 = s³

s = 3√125

s = 5 cm

Volume of the smaller can = 64cm³

64 = s³

s = 3√64

= 4

s = 4 cm

The ratio of sides of the smaller can to the larger can = 4 : 5

Surface area is a function of the square of the sides

smaller can = s²

= 4²

= 16

larger can = s²

= 5²

= 25

Surface area of the larger can= 50cm³

50 = 25x

x = 50/25

= 2

x = 2

Surface area of the smaller can = 16x

x = 2

Surface area of the smaller can = 16x

= 16 × 2

= 32 cm³

Surface area of the smaller can = 32cm³

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