In ΔJKL, \overline{JL} JL
is extended through point L to point M, \text{m}\angle JKL = (3x-16)^{\circ}m∠JKL=(3x−16)
∘
, \text{m}\angle LJK = (2x+15)^{\circ}m∠LJK=(2x+15)
∘
, and \text{m}\angle KLM = (8x-19)^{\circ}m∠KLM=(8x−19)
∘
. Find \text{m}\angle LJK. m∠LJK.

70

step-by-step explanation:

2*5=10

4*15=60

60+10=

70

the first one, all those points on the line just make a strait line.

all it means is function 3

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm