The lengths of pregnancies in a small rural village are normally distributed with a mean of 260 days and a standard deviation of 17 days. In what range would you expect to find the middle 98% of most pregnancies?

Rounded to the nearest  integer the range would be:

220 < x < 300

Step-by-step explanation:

For a 98%the Z-score is 2.326

then you calculate the interval using:

Mean +/- Z * standard deviation

In our case:

260 +/- 2.326 * 17 = between     220.458 and 299.542

Rounded to the nearest  integer would be:

220 < x < 300

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.