The nth term of a sequence is 3n^2 +4.work out the third term of this sequence

N is the term that you are looking for. it asked for the 3rd term so you replace n with 3.       now its :     3 x 3^2 + 4 . you use the order of PEMDAS:

P  arenthesis
E  xponents
M  ultipication
D  ivision
A  ddition
S  ubtraction

you start with parenthesis but there are none so now exponents. 3^2 is 3 x 3. that would be: 3 x 3 = 9.

now multiplication.    3 x 9 + 4.        3 x 9 = 27

now division. there is none. so now addition and there is.      27 + 4 = 31.

then subtraction but there is none. so now you are done.

the 3rd term is therefore 31.

i hope that i helped.

Ibelieve it's a. 2.2 - x = -10.85 (plz tell me if it's right : ) )