Graph the equation -2x+y=-4

x=(2,0)

y=(0,-4)

Step-by-step explanation:

x-intercept

let y=0

=-2x+0=-4

=-2x=-4-0

=-2x/-2=-4/-2

=x=2 → (2,0) → from center or 0 to 2 units right

y-intercept

let x=0

=-2(0)+y=-4

=0+y=-4

=y=-4-0

=y=-4 → (0,-4) → from center or 0 to 4 units down

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation:

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen