PT=y, TR=2x + 1, QT = 4y. TS = 5x + 13
Mathematics, 10.11.2020 07:00 paulmistykinman
Find the values of x and y in parallelogram PQRS.
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PT=y, TR=2x + 1, QT = 4y. TS = 5x + 13
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X=
and y=
Answers: 1
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Find the values of x and y in parallelogram PQRS.
R
PT=y, TR=2x + 1, QT = 4y. TS = 5x + 13
PT=y, TR=2x + 1, QT = 4y. TS = 5x + 13
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