An architect wants to design a rectangular room so that its length is 8 meters more than its width, and its perimeter is greater than 56 meters. If each
dimension of the room must be a whole number of meters, what are the
smallest possible measures, in meters, of the length and width?

the answer is b.)

< 1=< 2

i think its a and d

step-by-step explanation:

126 maybe. sorry

step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

simplifying:

to further simplify this radical, we need to use the property  

thus