If a" = 6", then n logax = m logb x
.

If students understand the basic proof on general laws of logarithm then it will be easie. ... loga (MN) = x + y = loga M + loga N [putting the values of x and y] ... a on both sides of the change of base rule formula [loga M = logb M × loga

Step-by-step explanation:

yall i think i got this wrong

even if it is to anyone who needs it just copy it lol

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~