George has $6.40 in nickels and dimes. If he has 32 more nickels than dimes, how many of each type
of coin does he have?

George has 64 nickel and 32 dimes.

Step-by-step explanation:

Normally, we have:

One nickel = 5 cents

One dime = 10 cents

One dollar = 100 cents

Therefore, total number of cents that George has can be calculated as follows:

Total number of cents = $6.40 * 100 = 640 cents

Based on the above, we have:

640 cents = 640 / 5 = 128 nickel

640 cents = 640 / 10 = 64 dimes

Therefore, we have:

128 nickel = 64 dimes

Divide through by 2 in order to share 640 cents equally, we have:

128 nickel / 2 = 64 dimes / 2 => 64 nickel = 32 dimes

Since 64 minus 32 is equal to 32, it therefore implies that George has 64 nickel and 32 dimes.

answer: the answer is 127 degrees

answer: the answer is b. i think hope i got it correct

step-by-step explanation: