Veronica is playing in a 32-player chess tournament. The probability of her playing exactly 1 game is 1/16, exactly 2 games is 1⁄4, exactly 3 games is 1/8, exactly 4 games is 1/8, and exactly 5 games is 3/16. Determine Veronica’s expected value.

Veronica’s expected value is 2.375.

Step-by-step explanation:

The expected value (EV) can be described as a value that is anticipated for an activity at some point in the future.

The expected value is computed by summing the product of each of the possible outcomes and the probability of occurrence of each outcome.

Therefore, Veronica’s expected value can be determined as follows:

Product of probability of her playing exactly 1 game and 1/16 = 1 * (1/16) = 1 * 0.0625 = 0.0625

Product of probability of her playing exactly 2 games and 1/4 = 2 * (1⁄4) = 2 * 0.25 = 0.50

Product of probability of her playing exactly 3 games and 1/8 = 3 * (1/8) = 3 * 0.125 = 0.375

Product of probability of her playing exactly 4 games and 1/8 = 4 * (1/8) = 4 * 0.125 = 0.50

Product of probability of her playing exactly 5 games and 3/16 = 5 * (3/16) = 5 * 0.1875 = 0.9375

Summing all the above together, we have:

Veronica’s expected value = 0.0625 + 0.50 + 0.375 + 0.50 + 0.9375 = 2.375

Therefore, Veronica’s expected value is 2.375.

-14

step-by-step explanation:

2x2 – 2(x+4)

=2x2-2（5+4）

=4-2×9

=4-18

=-14