A survey of 300 union members in New York State reveals that 112 favor the Republican candidate for governor. Construct the 90% confidence interval for the true population proportion of all New York State union members who favor the Republican candidate. Group of answer choices 0.308 < p < 0.438 0.301 < p < 0.445 0.316 < p < 0.430 0.327 < p < 0.419

Complete Question

A survey of 300 union members in New York State reveals that 112 favor the Republican candidate for governor. Construct the 98% confidence interval for the true population proportion of all New York State union members who favor the Republican candidate. Group of answer choices

A 0.308 < p < 0.438

B 0.301 < p < 0.445

C  0.316 < p < 0.430

D 0.327 < p < 0.419

The correction option is A

Step-by-step explanation:

From the question we are told that

   The sample size is  n  =  300

     Th number that are in favor is k = 112

   Generally the sample proportion is mathematically represented as  

=>        

=>          

From the question we are told the confidence level is  98% , hence the level of significance is    

=>  

Generally from the normal distribution table the critical value  of   is  

Generally the margin of error is mathematically represented as  

=>  

=>  

Generally 95% confidence interval is mathematically represented as  

=>  

=>  

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !