The hypotenuse of a triangle is 26 mm one leg of the right triangle is 10 mm what is the length of the other leg the options are 18 20 24 and 28

24 mm

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let x be the other leg, then

x² + 10² = 26²

x² + 100 = 676 ( subtract 100 from both sides )

x² = 576 ( take the square root of both sides )

x = = 24

The length of the other leg is 24 mm

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse