The base of a triangle is 4 meters shorter than the height. What are the height and length of the triangle if its area is 48 square meters? *

H=12 and B=8

Looking at the problem, you are given the area, a , and told the h is 4 meters longer than b; in other words, h=b+4.

Since a=1/2bh, you can replace a with 48. Also, since h is b+4, you can replace that as well. You'd end up with this equation:

48=1/2b(b+4)

1. Seeing that 48 is 1/2 of b, you know that you have twice the value of 48, or 96. So, you can put that 96=b(b+4).

2. Now, thinking through factors of 96-  1 x 96, 2 x 48, 3 x 32, 4 x 24, 6 x 16, or 8 x 12, the only pair in which h is b+4 is 12 x 8.

Hope this helps,

Lacia :))

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent