Solve. Which is the solution to 2^x=9^{x-9}

No solution

Step-by-step explanation:

1=9\left\{\left(-\frac{u-9\ln \left(2\right)}{\ln \left(2\right)}\right)-9\right\}e^{-\ln \left(2\right)\left(-\frac{u-9\ln \left(2\right)}{\ln \left(2\right)}\right)}

okay, this isn't as helpful but its for sure not A, cause I got it wrong, so it's either B, C, or D sorry broskis

Step-by-step explanation:

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: