Which quadratic equation models the main cable of the bridge correctly?
O y=0.048x^2 – 2494
y = 0.048x^2-6
y = 0.0048(x - 50)^2 + 6
y=0.0048(x - 6)^2 + 50

Option C is your answer Y=0.0048(x-50)^2 + 6

Step-by-step explanation:

Just completed it.

means if you're already damaged some way when you take out a medical insurance you will not get full compensation for that injury that you already have.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet