A ball is launched upward at 20 meters per second (m/s) from a 60 meter tall platform. The equation for the object’s height s at time t seconds after launch is s(t) = -4.9t^2+20t+60, where s is in meters. How long before the object hits the ground after launch?

for the points

step-by-step explanation:

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk

b.-4 units

all you   do is count how many times you move

what are the statments

step-by-step explanation: