Which of the following functions has the function rule y = x +4? Of(0, 2), (-2,-6), (1,5)}
O [(2, 6)(-3, -7), (0, 4)]
O f(-3,1),(0,4), (2, 6))
Of(-2, 2), (-1.-5), (3, 7))

Replace x with the given values and solve for y.

The answer is:

f(-3,1),(0,4), (2, 6))

can i see the following ?

step-by-step explanation:

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0