NEED ASAP Which value is the solution for the equation tanx/2=1
pi/2
pi/4
3pi/4
3pi/2

a ) π/2, 4π/3, 3π/2. 5π/3.

Step-by-step explanation:

2 sin t cos t + √3 cos t = 0

cos t ( 2 sin t + √3 ) = 0

Therefore:

cos t = 0,   t 1 = π/2,  t 2 = 3 π/2

or:

2 sin t + √3 = 0

2 sin t = - √3

sin t = - √3 / 2

t 3 = 4 π/3,  t 4 = 5 π/3

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

1. minimum

2. 6400

3. eight

hope this !