You notice a hot air balloon descending. The elevation h (in feet) of the balloon is modeled by the function h(x)=−11x+330, where x is the time (in seconds) since you first noticed the hot air balloon. Graph the function and specify its domain and range. Then interpret the slope and intercepts of the graph.

1) Please find attached, the graph of the function

The domain of the function is 0 ≤ x ≤ 30

The range of the function is 330 ≥ x ≥ 0

2) The slope of the given equation, shows that the elevation decreases, by (-)11 feet for each increase in time by one second

3) The y-intercept gives the initial elevation of the balloon at time t = 0 seconds

The x-intercept gives the final elevation of the balloon when it lands at time t = 30 seconds

Step-by-step explanation:

1) The function modelling the height of the balloon is h(x) = -11x + 330

Where;

x = The time of elevation of the balloon

The data for the graphing derived from Microsoft Excel are as follows

x       h(x)

0       330

5       275

10      220

15      165

20      110

25      55

30       0

Please find attached, the graph of the function

The domain of the function is 0 ≤ x ≤ 30

The range of the function is 330 ≥ x ≥ 0

Comparing the given function to the general equation of a straight line, y = m·x + c, we have that the slope, m = -11

2) The slope of a straight line graph gives the rate of change of the dependent variable, per unit change in the independent variable

Therefore, the slope of the given equation, -11 gives the rate of change of the function per unit increase in the independent variable x

Therefore, the elevation decreases, by (-)11 feet for each increase in time by one second

3) The y-intercept gives the initial elevation of the balloon at time t = 0 seconds

The x-intercept gives the final elevation of the balloon when it lands at time t = 30 seconds

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