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Solve for b 2 in A = h(b 1+b 2), if A = 16, h = 4, and b 1 = 3.

b 2 =

1

Step-by-step explanation: substitute all the corresponding terms so you get, 16=4(3+b2)

Then you multiply and get 16=12+4b2 then subtract 12 from both sides to get 4=4b2 and then divided both sides by 4 and you get 1=b2

1

Step-by-step explanation: A = h(b 1+b 2)

16=4(3+b2)

16/4=3+b2

4=3+b2

B2 =4-3=1

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answer: do we write it

step-by-step explanation: