Given that cosec A= -2, sec B= -2, A and B lie in the same quadrant. Find sin (2A+2B) help me please,

sin (2A+2B) = 0

Step-by-step explanation:

Given that,

cosec A= -2 and sec B= -2, A and B lie in the same quadrant.

We need to find the value of sin (2A+2B).

And

To find the value of sin (2A+2B) as follows :

sin [2(-30)+2(120)] = sin (-60+240)

=sin (180)

= 0

So, the value of sin (2A+2B) is qual to 0.

maya’s expression will generate the wrong sum because she violated the commutative property.

step-by-step explanation:

vertical asymptote .

horizontal asymptote .

step-by-step explanation:

given function is .

vertical asymptote is given by setting

denominator =0

when degree of numerator and denominator are same then divide first term of numerator by first term of denominator to get horizontal asymptote.