How do you find an equation for a line with a slope of 2/3 passing through (1,-4)

The standard general equation for a straight line is:

y = mx + C. You said the slope of line is 2/3. m is always the slope in this context. So with the numerical value slope we have the line

Y = 2/3 X + C. You also said the line passes through the point (1, -4) that is the X value is 1 and the y value is -4. Substitute these value into the linear equation to find C, as follows

-4 = 2/3 + c. and so C = - 4 - 2/3 = -14/3 and so the equation of line is :

y = 2x/3 + 14/3 or if you like 3y = 2x + 14

It is important to remember that the convention of the bracketted numbers e.g. (1,-4) or ( 1, -4, z), say is that the first number in the brackets indicates the X value, the second the y value and the third, the z value in the case of 3 D coordinates.

-81 -56 -27 0 81

step-by-step explanation:

add them

step-by-step explanation:

idk you did not give the options or numbers so you cant solve it