Sea ice is frozen ocean water, which freezes at a temperture of about -1.8 degress celsius. What is the temperture in fahrenheit use the formula F=(c) (9/5)+32

28.76 °F

Step-by-step explanation:

The temperture of sea ice frozen ocean water is about -1.8 °C .

We are to convert to a temperture in fahrenheit using the formula F=(c) (9/5)+32

°C = -1.8°C

°F=(c) (9/5)+32

= [(-1.8°C × 9/5) + 32]°F

= [-16.2/5 + 32]°F

= [-3.24 + 32]°F

= 28.76°F

the answer is 96 degrees

step-by-step explanation:

you have to realize that a line equals 180 degrees

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step-by-step explanation: