Use the following information for the questionThe average travel time to work for a person living in kokomo is 17 minutes. Suppose the standard deviation of travel time to work is 4.5 minutes and the distribution of travel time follows a normal distribution. Approximately what percentage of people living in Flint have a travel time to work that is less than 12.5 minutes?A) 15% B) 25% C) 75% D) None of these.

16%

Step-by-step explanation:

We solve using z score formula

= z = (x-μ)/σ, where

x is the raw score = 12.5 minutes

μ is the population mean = 17 minutes

σ is the population standard deviation = 4.5 minutes

z = 12.5 - 17/4.5

z = -1

Probability value from Z-Table:

P(x<12.5) = 0.15866

Converting to percentage

= 0.15866 × 100

= 15.866%

Approximately , the percentage of people living in Flint have a travel time to work that is less than 12.5 minutes is 16%

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation:

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y