A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the
time that the rocket will hit the ground, to the nearest 100th of second.
y = -16x2 + 247x + 141

15,99s

when the rocket hit the ground => y = 0

=> -16x² + 247x + 141 = 0 (*)

a = - 16      b = 247     c = 141

Δ = b² - 4ac = 247² + 16.4.141 = 70033 > 0 => (*) has 2 solutions

=> x =

or x =

Step-by-step explanation:

y=-2.5x+12.5

step-by-step explanation:

5y=2x+10

y=0.4x+2

slope=-2.5

5=-2.5*3+b

b=12.5