Helll Write the equation of the line passing through (2,3) and perpendicular to y = 2/3 x + 7.

A perpendicular line will, by definition, have the negative reciprocal of the slope of the original line, so we already know the slope of the new line is -1/4. Therefore, the second line has an equation of y = -1/4x + b, where b is the intercept. Since we have a point on this second line, we can solve for b (the intercept) by plugging in the x and y values of that point. Thus, 2 = -1/4(-12) + b. Simplifying, 2 = 3 + b, so b = -1. The equation of the second line is y = -1/4x - 1!

Step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

(-5,-28)

i graphed to on desmos.