Four identical right triangles whose sides measure 5x, 12x, and 13x are arranged to form a small square inside a large square, as shown. The perimeter of the large square is 17 units. What is the perimeter of the small square? Explain.

The perimeter of the small square is approximately 9.154 units

Step-by-step explanation:

The given parameters are;

The sides of the four identical right triangles = 5·x, 12·x, and 13·x,

The perimeter of the large square = 17 units

Therefore, we have;

The hypotenuse side of the right triangles = The longest side = 13·x

The sides of the large square are formed by the hypotenuse sides of the right triangle

Therefore, the perimeter of the large square = 4 × 13·x = 52·x = 17 units

x = 17/52 ≈ 0.3269

x ≈ 0.3269 units

The sides of the small square = The difference between the longer and the shorter of the two legs = 12·x - 5·x = 7·x

∴ The sides of the small square = 7·x = (7 ×  0.3269) units ≈ 2.2885 units

The perimeter of the small square = 4 × The sides of the small square

The perimeter of the small square ≈ (4 × 2.2885) units ≈ 9.154 units

The perimeter of the small square ≈ 9.154 units.

what

i believe that the answer is

b. y-1=-2(x-4)

hope this !