In a full set of permanent teeth, 1/4 of the teeth are incisors, 1/4 are premolars, and 3/8 are molars. What fraction of all the teeth are incisors, premolars, and molars

7/8

Step-by-step explanation:

In a full set of permanent teeth, 1/4 of the teeth are incisors, 1/4 are premolars, and 3/8 are molars. What fraction of all the teeth are incisors, premolars, and molars?

To solve the above, we add all the fractions together.

= Incisors + Premolars + Molars

= 3/8 + 1/4 + 1/4

Least Common Denominator = 8

= (3 × 1 + 2× 1 + 2 × 1)/8

= 3 + 2 + 2/8

= 7/8

Hence, the fraction of all the teeth are incisors, premolars, and molars is 7/8

ome people is not even worth it to even try it in the air.

step-by-step explanation:

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.