2. the following formula relates three quantities: force (f), mass (m), and acceleration (a).
f = ma
(a) solve this equation for a.
(b) let the force be units and the mass be m = 10 units. what is the acceleration, a?
(c) let the force be f = 25 units and the acceleration be a = 5 units. what is the mass, m?

Step-by-step explanation:

(a) Since we have F  = ma and we have to solve for a

                     there is multiplication between m and a and in order to solve for a ,we need to apply opposite operation of  multiplication ,therefore dividing both sides by m ,we get

(b)  Let F be the force and m = 10 units is mass

        acceleration =   [ If we have given value of F then we divide the value of F by 10 to get acceleration  value.

                               =

(c)   Mass m  will be  given by equation

step-by-step explanation:

a and d

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!