Find three consecutive odd integers such that the sum of the first, two times the second, and three times the third is 70

9, 11 and 13

Step-by-step explanation:

Let the integers be x, x + 2, x + 4.

x + 2(x + 2) + 3(x + 4) = 70

x + 2x + 4 + 3x + 12 = 70

6x = 54

x = 9

therefore the three integers are 9, 11 and 13

This is a question on forming and solving algebraic equations. If you wish to venture further into it/understand this topic better, you may want to follow my Instagram account (learntionary), where I post some of my own notes on certain topics and also some tips that may be useful to you :)