Given that a_n= 3a _ n-1 +1 were a_1=2 whats the 3rd -6th terms of the sequence

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: