If a(2x-3)=bx+5 then the solution for x in terms of a and b is

x=(3a+5)/(2a-b)

Step-by-step explanation:

first we distribute the a to the 2x and -3

2ax -3a=bx+5

we move the -3a over by adding 3a

2ax=bx+5+3a

then we move the bx over

2ax-bx=5+3a

we can now group the left side like this

x(2a-b)=5+3a)

to find x all we must do is divide both sides by (2a-b)

x=(3a+5)/(2a-b)

30

step-by-step explanation:

idk

i hope i

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it