= 
+ 
[ (x - 1)(x - 2) ≠ 0 ⇒ x ≠ 1 and x ≠ 2 ] 
= 0 
= 0 
= 3 ( one acceptable solution ) 
= 2 is an extraneous solution 
answer choice and 
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Mathematics, 13.11.2020 18:10 silverns
I REALLY NEED YOUR HELP GUYS PLEASE HELP ME ANSWER MY QUESTION PLEASE HELP!!
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